AND, independent events
Independent (one doesn't change the other: coin & die, with replacement, a fixed %) → P(A and B) = P(A) × P(B).
- Coin + die: tail AND even = 1/2 × 3/6 = 1/4 (exam Q15).
- Repeated % events: none of 4 text (35% do) = (.65)⁴ = .179.
- Both drives fail at 3% each: .03² = .0009.
Traps
- Added the probabilities for AND.head and 4 → 1/2 + 1/6✓ 1/2 × 1/6 = 1/12 (exam Q14)
- Shrank the pool when the item was replaced.two queens replaced → 4/52 × 3/51✓ replaced → (4/52)² = 1/169